Dear list,
if there is [adddollar( is there [removedollar( too?
I want to pack an unknown amount of numbers to a list, between 1-10. it can be once 5, later 3 etc.
Is it possible with pd?
Best, Popesz
On 12/17/20 1:22 PM, Csaba Láng wrote:
Dear list,
if there is [adddollar( is there [removedollar( too?
I want to pack an unknown amount of numbers to a list, between 1-10. it can be once 5, later 3 etc.
Is it possible with pd?
how would [removedollar( help you here? in your problem description i don't see the need to *remove* anything. so what do you expect [removedollar( to do?
what's wrong with [list store]? and if you want to stay old-school, what's wrong with [add2(?
gfadsmr IOhannes
Iohannes, thanks for your prompt answer. The reason I thought of removedollar, to not have 10 elements on the ranking, but just 3, if 3 people compete. Looks like [list store] will be the easiest choice.
Thanks once again,
Popesz
On Thu, Dec 17, 2020 at 1:43 PM IOhannes m zmoelnig zmoelnig@iem.at wrote:
On 12/17/20 1:22 PM, Csaba Láng wrote:
Dear list,
if there is [adddollar( is there [removedollar( too?
I want to pack an unknown amount of numbers to a list, between 1-10. it
can
be once 5, later 3 etc.
Is it possible with pd?
how would [removedollar( help you here? in your problem description i don't see the need to *remove* anything. so what do you expect [removedollar( to do?
what's wrong with [list store]? and if you want to stay old-school, what's wrong with [add2(?
gfadsmr IOhannes
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Csaba Láng -
IOhannes m zmoelnig