Iohannes,

thanks for your prompt answer.

The reason I thought of removedollar, to not have 10 elements on the ranking, but just 3, if 3 people compete.

Looks like [list store] will be the easiest choice.

Thanks once again,

Popesz

On Thu, Dec 17, 2020 at 1:43 PM IOhannes m zmoelnig <zmoelnig@iem.at> wrote:

On 12/17/20 1:22 PM, Csaba Láng wrote:
> Dear list,
>
> if there is [adddollar( is there [removedollar( too?
>
> I want to pack an unknown amount of numbers to a list, between 1-10. it can
> be once 5, later 3 etc.
>
> Is it possible with pd?

how would [removedollar( help you here?
in your problem description i don't see the need to *remove* anything.
so what do you expect [removedollar( to do?

what's wrong with [list store]?
and if you want to stay old-school, what's wrong with [add2(?

gfadsmr
IOhannes

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