hi, how can i make a reciprocal square root without using the rsqrt~ object? i know rsqrt (x) = 1/sqrt(x) and im trying [sig~ 1]-> [/~ ]<- [sqrt~ x] but i cant put signals to the right inlet of /~ , when i put an unsig~ it doesnt work , i need a signal because i want to connect the result to rifft~
any idea?
thanks in advance
siggmus
hi siggmus,
it should work exactly as you described... make sure, that you don't write a default value (like /~ 1) to the dividetilde, because then only messages ar accepted.
marius.
On Sun, 18 Apr 2004 01:58:07 -0700 "siggmuss" siggmus@fastmail.fm wrote:
hi, how can i make a reciprocal square root without using the rsqrt~ object? i know rsqrt (x) = 1/sqrt(x) and im trying [sig~ 1]-> [/~ ]<- [sqrt~ x] but i cant put signals to the right inlet of /~ , when i put an unsig~ it doesnt work , i need a signal because i want to connect the result to rifft~
any idea?
thanks in advance
siggmus
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hi siggmus,
forgot to say you could also use [expr~ 1/sqrt~($v1)]
m.
On Sun, 18 Apr 2004 01:58:07 -0700 "siggmuss" siggmus@fastmail.fm wrote:
hi, how can i make a reciprocal square root without using the rsqrt~ object? i know rsqrt (x) = 1/sqrt(x) and im trying [sig~ 1]-> [/~ ]<- [sqrt~ x] but i cant put signals to the right inlet of /~ , when i put an unsig~ it doesnt work , i need a signal because i want to connect the result to rifft~
any idea?
thanks in advance
siggmus
-- http://www.fastmail.fm - One of many happy users: http://www.fastmail.fm/docs/quotes.html
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