Hi all -

I believe the general formula for Hann is to divide by (3/8 * overlap * window size).

this assumes that the inout and output are both Hann windowed, therefore you're really dindowing by the square of the Hann window whose average over N points is 3/8.

cheers Miller

On Fri, Oct 12, 2012 at 05:44:20PM -0500, Charles Henry wrote:

On Fri, Oct 12, 2012 at 4:59 PM, Alexandre Torres Porres porres@gmail.com wrote:

...

hi there, in pd's examples, we need to divide by (3/2 * window size) in a 4 overlap on a hann window.

what about other overlaps, what is the normalizing factor?

and how about other windows?

I looked for this info on books and google and stuff, found nothing.

Engineers, please help.

thanks Alex

I'm not exactly sure why it's used either. If you were using a overlap of 2 and used hann windows that cover each block, you would get back the exact signal after applying overlap-and-add with no additional normalization.

So, for the same scheme and overlap 4, it stands to reason that you'd only divide by 2 and recover the original signal as well.

What's the window size like relative to the block size? same/different?

Some other engineer--please help.

Chuck

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