Hello list, this is just a curiosity of mine
When we create [pd test] we can send messages to pd-test, so if i send [;pd-test vis 1] it will show up.
But if i create an abstraction "test", [; test vis 1] doesn't work, i am assuming that i need to put a namecanvas there, but, is it possible to access it without namecanvas?
as a further question, a cloned abstraction also could be accessed without namecanvas? even just the first instance
(there is nothing wrong for me in putting [namecanvas test$1] inside the clone, this is just a curiosity about how these auto created names works)
On 3/5/21 6:49 PM, José de Abreu wrote:
Hello list, this is just a curiosity of mine
When we create [pd test] we can send messages to pd-test, so if i send [;pd-test vis 1] it will show up.
But if i create an abstraction "test", [; test vis 1] doesn't work, i am assuming that i need to put a namecanvas there, but, is it possible to access it without namecanvas?
yes.
you can use "pd-<abstractionname>.pd" (e.g. "pd-test.pd").
however, i would strongly discourage you from doing so: all instances of the same abstraction have that name, so they will all become visible. use [namecanvas] to give your abstraction a unique label, or iemguts' [sendcanvas] which doesn't require a label at all.
for subpatches, you can easily create unique names, e.g. [pd $0-foo]
as a further question, a cloned abstraction also could be accessed without namecanvas? even just the first instance
this is covered in the helppatch of [clone].
fdmsar IOhannes
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IOhannes m zmölnig -
José de Abreu