hi,

Am Mittwoch, 2. August 2006 15:26 schrieb Frank Barknecht:

Hallo,

João Miguel Pais hat gesagt: // João Miguel Pais wrote:

...

I have a (variable) flow of ascending numbers triggered from until. I wanted to separate them into even and odd ones, so that each becomes a different treatment (eg. even get 0ed, odd get divided by 2). Is there a modulo option in expr? With that and an [expr if] it should be easy. Or does anyone has any other suggestions?

[t a a]

| \

[mod 2] \

[pack 0 0]

[route 0 1]

I think, expr also has "mod" or "%"

Ciao

if pd provides the bitwise and operator, you may simply check the number for its lowest bit ( & 0x01 )... if set, its uneven, if clear, its an even number. this works only on integers of course.

but it is definitely cheaper than the modulo operator (cpu-wise)....

greets,

chris

On 8/2/06, Frank Barknecht fbar@footils.org wrote:

Hallo, Christian Klippel hat gesagt: // Christian Klippel wrote:

...

if pd provides the bitwise and operator, you may simply check the number for its lowest bit ( & 0x01 )... if set, its uneven, if clear, its an even number. this works only on integers of course.

This is a good idea. THe object to use is [& 1] as in attached patch.

Is this more efficient?