AW> I need to round down a float. Right now the value (which is timer actually) AW> is something like 24.4648736 AW> I need it to be 24.5 in this case.

dunno if there's a round external somewhere but you could subtract a float number from its integer equivalent with [int ] then use [moses ] to determine when you should keep the original or increment with 0.1

no time right now to make you the patch, but this should not be too hard using those 2 objects and some operators.

bests

++ aymeric. http://bleu255.com

Hi,

I made an abstraction a while ago which can do this. Unfortunately it is named in german ("runden"). You can also give an argument like runden 4 which would round floats to 99.1234. default is to round to no commas.

find it at

http://www.parasitaere-kapazitaeten.net/Pd/pdpatches/index.htm resp. http://www.parasitaere-kapazitaeten.net/Pd/pdpatches/runden.pd

Marius.

----- Original Message ----- From: "Anton Woldhek" woldhek@xs4all.nl To: PD-list@iem.at Sent: Monday, February 09, 2004 10:58 PM Subject: [PD] [newbie] rounding

Hi everybody,

I was pretty active with PD for a while, but got kinda side-tracked unfortunatly. Anyways, if somebody could be so kind to help me back in the saddle. I need to round down a float. Right now the value (which is timer

actually)

is something like 24.4648736 I need it to be 24.5 in this case. I couldnt find an object to do this.

But

im sure ive missed something, as i know ive done this before.

thanks for the help Anton

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