Thanks VERY much, Johannes. I hope to learn from these basic problems.

Best wishes,

Richard.

| hi | | the first inlet starts counting, the second one triggers the output ot the | time that has elapsed since counting was started. | therefore you have to make sure, that you trigger the second inlet before | the first one (so that you read out the elapsed time, before you reset it | to zero) | with good look you can do this they way you tried: | make a |bang( and a |timer| object. | FIRST connect the |bang( outlet with the SECOND inlet of the |timer| | THEN connect the |bang( outlet with the FIRST inlet of the |timer| | but this is VERY BAD STYLE (and maybe it will stop working sometimes in | the future. who knows ?) | | the clean solution would be | =----- | |bang( | =----- | | | =------ | |t b b| | =-----= | | | | =-----= | |timer| | =------ | | | =------------ | |print delta| | ------------- | | the trigger-object ("t", "trigger") makes sure that its outlets are | triggered from right to left (outlet on the right hand comes first, the | leftest one will be the last) | | everytime you must assure that messages are send in a special order, you | really HAVE to use the trigger-method (though you could might get it to | work, as i have shown above) | | make fun | mfg.fsd.sad | IOhannes | | | On Wed, 23 May 2001, richard.bowers wrote: | | > Hi, | > | > I'm having a seriously fundamental problem here. I'm trying to use the timer | > to give the delta time for MIDI notes. The attached patch can only give 0 | > delta times because the bang goes into each inlet in quick succession. | > | > Can anyone offer a solution? | > | > Richard. | > |