thanks for the answers, i will try all and post the results ;)
On Tue, Apr 27, 2010 at 11:06 PM, Matt Barber brbrofsvl@gmail.com wrote:
Ha ha, mine had a hilarious and totally unnecessary extra [list-map]. That's what happens when you work hastily... how embarrassing; oh well.
MB
On Tue, Apr 27, 2010 at 9:13 PM, Jack jack@rybn.org wrote:
True, so now it should be OK (patch attached). I didn't think of this eventuality. ++
Jack
Le mardi 27 avril 2010 à 20:50 -0400, Matt Barber a écrit :
One thing to watch out for; if you get two items in the list that are equally as far as the test value, mine outputs one list with the value replacement at each appropriate index, while Jack's outputs several lists with the value replacement at only one index, but each replacement sequentially, if that makes any sense.
So if the test value is 2.02, and the input list is <1 0 3 2 4 3 3 2 0 4>, mine will output:
<1 0 3 2.02 4 3 3 2.02 0 4> as one list, while Jack's gives two lists:
<1 0 3 2.02 4 3 3 2 0 4> <1 0 3 2 4 3 3 2.02 0 4>
Matt
On Tue, Apr 27, 2010 at 8:16 PM, Jack jack@rybn.org wrote:
An alternative. Also full pure-pd. ++
Jack
Le mardi 27 avril 2010 à 18:49 -0400, Matt Barber a écrit :
Try the attached (threw together using list-abs) -- right inlet is
the
value (12 in your example) and left inlet is the list of floats; I think this follows established list-abs syntax.
It's possible that I overlooked a list-abs that already does this,
and
there is probably a step or two you could skip.
You might get poor results if the list is a bang or contains symbols.
Matt
Hello everyone,
I would like to compare all the values in a list with a value of
input and
then decide which is the closest value and replace that value
closer to the
amount of input.
For example, I have a list <2, 10, 35> and have an input value of
<12> I
would like the list as output <2, 12, 35>. I'm almost getting, but
the patch
is so ugly that I will not show here, i'm sure there is a more
elegant
solution. Does anyone have an idea? tnx ;)