On Tue, Apr 27, 2010 at 9:13 PM, Jack <
jack@rybn.org> wrote:
> True, so now it should be OK (patch attached).
> I didn't think of this eventuality.
> ++
>
> Jack
>
>
>
> Le mardi 27 avril 2010 à 20:50 -0400, Matt Barber a écrit :
>> One thing to watch out for; if you get two items in the list that are
>> equally as far as the test value, mine outputs one list with the value
>> replacement at each appropriate index, while Jack's outputs several
>> lists with the value replacement at only one index, but each
>> replacement sequentially, if that makes any sense.
>>
>> So if the test value is 2.02, and the input list is <1 0 3 2 4 3 3 2 0
>> 4>, mine will output:
>>
>> <1 0 3 2.02 4 3 3 2.02 0 4> as one list, while Jack's gives two lists:
>>
>> <1 0 3 2.02 4 3 3 2 0 4>
>> <1 0 3 2 4 3 3 2.02 0 4>
>>
>> Matt
>>
>> On Tue, Apr 27, 2010 at 8:16 PM, Jack <
jack@rybn.org> wrote:
>> > An alternative. Also full pure-pd.
>> > ++
>> >
>> > Jack
>> >
>> >
>> >
>> > Le mardi 27 avril 2010 à 18:49 -0400, Matt Barber a écrit :
>> >> Try the attached (threw together using list-abs) -- right inlet is the
>> >> value (12 in your example) and left inlet is the list of floats; I
>> >> think this follows established list-abs syntax.
>> >>
>> >> It's possible that I overlooked a list-abs that already does this, and
>> >> there is probably a step or two you could skip.
>> >>
>> >> You might get poor results if the list is a bang or contains symbols.
>> >>
>> >> Matt
>> >>
>> >>
>> >> > Hello everyone,
>> >> >
>> >> > I would like to compare all the values in a list with a value of input and
>> >> > then decide which is the closest value and replace that value closer to the
>> >> > amount of input.
>> >> >
>> >> > For example, I have a list <2, 10, 35> and have an input value of <12> I
>> >> > would like the list as output <2, 12, 35>. I'm almost getting, but the patch
>> >> > is so ugly that I will not show here, i'm sure there is a more elegant
>> >> > solution. Does anyone have an idea?
>> >> > tnx ;)
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