Hi all -
I believe the general formula for Hann is to divide by (3/8 * overlap * window size).
this assumes that the inout and output are both Hann windowed, therefore you're really dindowing by the square of the Hann window whose average over N points is 3/8.
cheers Miller
On Fri, Oct 12, 2012 at 05:44:20PM -0500, Charles Henry wrote:
On Fri, Oct 12, 2012 at 4:59 PM, Alexandre Torres Porres porres@gmail.com wrote:
hi there, in pd's examples, we need to divide by (3/2 * window size) in a 4 overlap on a hann window.
what about other overlaps, what is the normalizing factor?
and how about other windows?
I looked for this info on books and google and stuff, found nothing.
Engineers, please help.
thanks Alex
I'm not exactly sure why it's used either. If you were using a overlap of 2 and used hann windows that cover each block, you would get back the exact signal after applying overlap-and-add with no additional normalization.
So, for the same scheme and overlap 4, it stands to reason that you'd only divide by 2 and recover the original signal as well.
What's the window size like relative to the block size? same/different?
Some other engineer--please help.
Chuck
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