On Sat, 2010-03-27 at 14:30 +0100, Matteo Sisti Sette wrote:
However, the $0 is not handled properly. It is immediately "interpreted" and becomes a 0, as Ben described.
If it would be interpreted, the number would be >= 1000, but not 0. AFAIK, $0-counting starts at 1000.
This is definitely a bug: there's no reason why $0 should be treated differently than $n with n>0.
my words.
Roman