30 Jan
2014
30 Jan
'14
6:45 p.m.
On Thu, Jan 30, 2014 at 10:58 AM, Alexandros Drymonitis adrcki@gmail.comwrote:
On Thu, Jan 30, 2014 at 6:36 PM, Charles Z Henry czhenry@gmail.comwrote:
If you want to use a contribution from both of your axes, you can just sum them together. (x+y)*sqrt(2)/2 is just a projection along the line x-y=0
Let me correct myself: the line is x+y=0
Can't really try it right now, but just to be sure, the last equation is to be interpreted like this: (x+y)*(sqrt(2)/2) or like this: ((x+y)*sqrt(2))/2?
It's the same either way. That's only needed if you want to be exact in
the projection value.