21 Aug
1999
21 Aug
'99
2:58 p.m.
reine@mbox314.swipnet.se writes:
Here are my guesses: The 2 in (2<<16) refers to number of fragments. The 14 refters to size of fragments. 14 bits is 16384. (correct me if im wrong).
this is exactely right. The parameter is fragmentnumber<<16 + log2(fragmentsize)
It seems like if I stay on a total of 32768 (=2*16384) I can use a number of variations like svar=(4<<16) | (13);
This is funny behaviour and will get you rather high latency (assuming that you can't use the GETOSPACE calls either)
BTW, what driver are you using ?
Guenter