24 Jul
2007
24 Jul
'07
7:46 a.m.
On Mon, 23 Jul 2007, B. Bogart wrote:
Mathieu, are you really able to put 8.0 in an expr argument? In my PD (.39 ubuntu package) the 8.0 gets turned into 8 and remains an int.
Ah! [expr float(8) / 6] does the trick, I'm damn happy there is float() in there!!!
if you write any character next to the number that causes pd to read it as a symbol, then pd won't rewrite it before expr reads it.
[expr (8.0) / (6.0)] = 1.25 [expr 8.0 / 6.0] = 1 [expr 8.0 /6.0] = 1.25 [expr 8.0/ 6.0] = 1.25 [expr 8.0/6.0] = 1.25
_ _ __ ___ _____ ________ _____________ _____________________ ... | Mathieu Bouchard - tél:+1.514.383.3801, Montréal QC Canada