hi,
well, we already explained that what is actually received in a perform routine is a block of n samples not always 256 !!
the n value within a patch is set by a [block~ N] object, where N is a power of two ( can be 256 or anything, you don't know how your object will be used ).
next, if you want to store audio blocks in a 256 array, you've got to have a counter which reminds your writing position like :
{ t_int counter; }
..._perform( ...... ) {
for(i=0; i<n; i++)
{
aleftout[counter] = *(in1++);
counter=(counter+1)%256;
arightout[counter] = *(in2++);
counter=(counter+1)%256;
}
}
restitution is the same problem reverted.
bye,
sevy/yves
J. Scott Hildebrand wrote:
the other question is this; i will end up having my convolvedsamples in an array like:
aleftout[256] arightout[256] what i need to do now is read those out to the soundcard, andoriginally i thought something like this would work:
for(int read=0; read<=255; read++) { out1++ = aleftout[read]; out2++ = arightout[read]; } well it doesn't work, and i'm not really sure what the mechanism isto get the samples back into the in/out arrays and then sent to the soundcard. any help is appreciated greatly!
scott
"640K ought to be enough for anybody." -- Bill Gates, 1981
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