thanks, sort is indeed lost faster than an abstraction. but still to slow for an audio rate median filter. I guess it's worth writing an external for this task (that would benefit from the fact that most input list are identical)
cheers c
Le 23/12/2016 à 23:31, Christof Ressi a écrit :
Hmmm. If doesn't have to be a vanilla solution, I would use zexy/sort and then get the middle element. It won't get much faster then that i guess.
Gesendet: Freitag, 23. Dezember 2016 um 23:17 Uhr Von: "cyrille henry" ch@chnry.net An: pd-list@lists.iem.at Betreff: Re: [PD] array quantile problem
Hhanks for the explanation.
I think the "so for instance, the 0.5 quantile is the median of the array." sentence of the documentation is confusion.
anyway, is there a fast way to get the median of a list? (faster than ordering the list with an abstraction and getting the middle value)
thanks Cyrille
Le 23/12/2016 à 22:58, Christof Ressi a écrit :
The array doesn't represent a list of values but rather a distribution of values where each y represents the weight of its x value. Changing your list to 1 2 3 4 5 6 7 8 9 will make it more clear to understand because the actual values are then: 0 1 1 2 2 2 3 3 3 3 4 4 4 4 4 5 5 5 5 5 5 6 6 6 6 6 6 6 7 7 7 7 7 7 7 7 8 8 8 8 8 8 8 8 8. Therefore 6 is the correct median.
Christof
Gesendet: Freitag, 23. Dezember 2016 um 21:55 Uhr Von: "cyrille henry" ch@chnry.net An: "pd-list@lists.iem.at" pd-list@lists.iem.at Betreff: [PD] array quantile problem
Hello,
I'm trying to use the [array quantile] object, but it is not doing what I understand from the documentation. the help file specify that the 0.5 quantile is the median. I'm using the wikipedia definition of the median : https://en.wikipedia.org/wiki/Median
So the list (0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9) admit 0.5 as median.
[array quantile] return 6.
In attachment, a patch that demonstrate this behaviours, and other list that return value that I did not expect.
I'm using pd 47.1. Did I made something wrong, or is that just a bug in [array quantile]?
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