Re: [PD] To divide a number in random parts

So, then use [randomF], put the values into an list/array and shuffle that. It would still be not fully random, because the numbers won't be bigger than 10, but still it would be quite random :)

On 04.03.2011 04:01, Caio Barros wrote:

    You could try this approach(I also attached a patch with it):
    48 = 4 * 10 + 1 * 8
    so you use
    n1=random(10)
    n2 = 10 - n1
    n3 = random(10)
    n4 = 10-n3
    .
    .
    n9 = random(8)
    n10 = 8 - n9


But this makes the odd-ordered chords to start at every 10 seconds. I
believe that Caio wants something more random than that.

Yes that's right. And another problem is that all the durations are integers. I want something without the feeling of (regular) pulsations.

BTW I have another idea :

initialise all of them to equal or almost equal amounts, then modify the
delays gradully : pick a donor randomly among delays that aren't already
minimum ; pick a acceptor randomly among delays that aren't already
maximum ; give one unit of delay from the donor to the acceptor.

I was trying to figure out something like that. Now that I think about it, is more important to have a minimum duration than a maximum because depending on the minimum I chose, the probability of a chord too long is low (and bottom line I can always change the result to fit in what I want to hear).

I'll need to experiment a bit. If I have the time to make a cool patch with general paramethers I'll share with the list. Unfortunately today I could not compose.

Caio Barros