Le 2011-10-31 à 07:10:00, ronni montoya a écrit :
HI I have an abstraction generating numbers permanently , i have the output connected to a "Number", i would like to only let pass one value each 10 times it changes. I was wondering if there is a easy way of doing this in pd? Or should i build a mechanism with spigots and metronome?
GridFlow has [shunt 10, mode 1] which outputs each incoming message to a different outlet, in a set of 10 outlets. You can use that to get only one message out of 10. For your specific case, you still need a [change]. This makes a solution in 2 objects (instead of 7 with plain pd).
See help file : http://gridflow.ca/help/shunt-help.html
As a shortcut, all options in the inlet 0 section can be put inside the objectbox using the comma (as in my example).
| Mathieu BOUCHARD ----- téléphone : +1.514.383.3801 ----- Montréal, QC