Hallo, joel silvestre hat gesagt: // joel silvestre wrote:
I'm searching how to do a sample resolution audio delay. Is it possible?
Yes, even in multiple ways: One would involve [rzero~]. rzero acts like this on audio input:
y[n] = x[n] - a[n] * x[n-1]
y[n]: output sample n x[n]: input sample n
If you set a = 1 and substract this from the original signal, you get:
y[n] = x[n] - (x[n] - x[n-1]) = x[n-1]
You could also set a = -1 and substract the original from rzero's output:
y[n] = (x[n] + x[n-1]) - x[n]) = x[n-1]
Both are a one sample delays. In Pd the first approach would realised as:
[inlet~]
|
| [rzero~ 1]
| |
[-~]
|
[outlet~]
Another way would be to use a normal delay with [delwrite~] and [delread~] and set the delay time to be one sample. One sample at a samplerate SR takes 1/SR seconds or 1000/SR milliseconds, so do this:
[samplerate~] | [swap 1000] | / [/~ ] | [* 1] | [delread~ mydelay]
Use this approach if you want to calculate delay times with more than one sample. Just change the [* 1] to [* 5] to get a delay of five samples, for example.
Ciao