An alternative. Also full pure-pd. ++
Jack
Le mardi 27 avril 2010 à 18:49 -0400, Matt Barber a écrit :
Try the attached (threw together using list-abs) -- right inlet is the value (12 in your example) and left inlet is the list of floats; I think this follows established list-abs syntax.
It's possible that I overlooked a list-abs that already does this, and there is probably a step or two you could skip.
You might get poor results if the list is a bang or contains symbols.
Matt
Hello everyone,
I would like to compare all the values in a list with a value of input and then decide which is the closest value and replace that value closer to the amount of input.
For example, I have a list <2, 10, 35> and have an input value of <12> I would like the list as output <2, 12, 35>. I'm almost getting, but the patch is so ugly that I will not show here, i'm sure there is a more elegant solution. Does anyone have an idea? tnx ;)