30 Mar
2009
30 Mar
'09
5:39 p.m.
Hallo, Frank Barknecht hat gesagt: // Frank Barknecht wrote:
Hallo, Derek Holzer hat gesagt: // Derek Holzer wrote:
[phasor~] [r~ shape] [expr~ if($v1<$v2,$v1/$v2,(1-$v1)/(1-$v2))]
Ah, but can you explain in non-technical English why this works?
Remember our reader base aren't mathematicians like Miller ;-)A past post by me describes a different algorithm (without skew) but it shows the generation of a triangle from a phasor using a message analogy: http://lists.puredata.info/pipermail/pd-list/2006-11/044253.html which I find quite intuitive.
Ups: Use that instead: http://lists.puredata.info/pipermail/pd-list/2006-11/044256.html
Ciao
Frank