27 Aug
2002
27 Aug
'02
12:36 p.m.
hi Frank,
"fexpr~ $x1[-2] - $x1[-1]" should work. Btw, the same calc could be done more efficiently with the z~ from zexy, or, even, with the biquad~.
Krzysztof
Frank Barknecht wrote: ...
I tried something like "fexpr~ $x1[2]-$x1[1]" but that gave me only a stream of "0"s when printed out with print~, even if I feed it a phasor~, which never has two values the same in its signal vector, so