Le 01/09/2010 10:37, Ed Kelly a écrit :
Thanks for unlocking my broken trig head.
This should really be in the documentation. The angle is in radians. Patch enclosed...
no, the angle is not in radian. in fact, shear is a non rotational space distortion, there is no angle...
shear distord 1 direction in relation to the coordinate on a 2nd direction. As Claude explain, you can calculate an angle from this distortion, based on 2 dimension. The tan object is in radian. that's the only thing in radian.
Cyrille
Best, Ed
Metastudio 3 for Pure Data - Free download at: http://sharktracks.co.uk/puredata
----- Original Message ---- From: Claude Heiland-Allenclaudiusmaximus@goto10.org To: Ed Kellymorph_2016@yahoo.co.uk Cc: PD Listpd-list@iem.at Sent: Wed, 1 September, 2010 1:09:43 Subject: Re: [PD] GEM Shear / angle relationship
Hi Ed,
On 31/08/10 15:31, Ed Kelly wrote:
Can anyone tell me how to calculate the 'shear' value (when using [shearYX] in Gem) from an angle (degrees or radians, I don't mind)?
This is just a guess, for one direction of shear in 2D space:
shear = tan(angle) (the angle marked ** in the ascii diagram below)
| __________ |**/ / | / / |/_________/
(because tan(0) = 0, tan(45deg) = 1, tan(90deg) = inf)
Otherwise try drawing triangles and doing some trigonometry (in a right-angle triangle: sin=opposite/diagonal cos=adjacent/diagonal tan=opposite/adjacent )
Claude -- http://claudiusmaximus.goto10.org
Pd-list@iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list