I've had the 6-digit problem trying to print UTM position coordinates
out of Pd.
If you know the range of your numbers, there are some ugly hacks that
provide a limited solution.
Eg, for 1234.5678 you can pass the number through [int] and then
subtract that from the original number to get the parts before and
after the decimal, then print them separately and use external scripts
to concatenate - or maybe you could convert them to symbols and
concatenate in Pd before printing.
You could do similar things using [mod] for numbers above 1e+06, etc...
Nick
On Nov 7, 2008, at 10:08 AM, Roman Haefeli wrote:
On Fri, 2008-11-07 at 09:45 +0100, IOhannes m zmoelnig wrote:
Mark Sexton wrote:
Hi I need PD to make simple but accurate calculations for a
sonification project. However there seems to be a problem working
accurately with floats that have 7 or more digits in total (before
or after the decimal point). PD always seem to round the figure to
6 digits whether in a calculation, or even typing a 7+ digit float
into a number box e.g. 1234.5678 rounded to 1234.57I've got a couple of ugly hacks to work around for now, but it
seems a fairly fundamental thing to do, so would be grateful to
hear if I'm missing a simple way to get PD to work accurately with
floats of any arbitrary length above 6 digits.you don't need anything. Pd does uses IEEE floating point values for numbers, you don't
loose a single bit. it's only the GUI that likes to round the numbers when displaying it. internally everything is "correct" (as far as it is possible using single precision floats)you could change the "width" of a number-box to see more digits.
still only 6 digits are displayed. altough pd works internall with
IEEE 32bit floating values, i couldn't think of an easy way to get them out of pd. both, print and the numberbox truncate the numbers.two ways - not very feasible, though - to get full precision out of pd come to my mind:
- send the numbers over OSC to some other application
- write the numbers to an audio file with 32bit bitlength. extract the
numbers from there
or has someone a better idea?
roman
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