hi

the first inlet starts counting, the second one triggers the output ot the time that has elapsed since counting was started. therefore you have to make sure, that you trigger the second inlet before the first one (so that you read out the elapsed time, before you reset it to zero) with good look you can do this they way you tried: make a |bang( and a |timer| object. FIRST connect the |bang( outlet with the SECOND inlet of the |timer| THEN connect the |bang( outlet with the FIRST inlet of the |timer| but this is VERY BAD STYLE (and maybe it will stop working sometimes in the future. who knows ?)

the clean solution would be

|bang(

|

|t b b|

| |

|timer|

|

|print delta|

the trigger-object ("t", "trigger") makes sure that its outlets are triggered from right to left (outlet on the right hand comes first, the leftest one will be the last)

everytime you must assure that messages are send in a special order, you really HAVE to use the trigger-method (though you could might get it to work, as i have shown above)

make fun mfg.fsd.sad IOhannes

On Wed, 23 May 2001, richard.bowers wrote:

Hi,

I'm having a seriously fundamental problem here. I'm trying to use the timer to give the delta time for MIDI notes. The attached patch can only give 0 delta times because the bang goes into each inlet in quick succession.

Can anyone offer a solution?

Richard.