On Mon, 26 Jun 2006, Federico wrote:
is there an object to compute the derivative function of a signal? f(x)=x => f'(x)=1
[rzero~ 1] times a constant.
and a more question: has this anything to do with complex signals or fourier?
Fourier(f')(w) = i*w*Fourier(f)(w)
so in the frequency domain, a derivative can be achieved by multiplying the spectrum by an imaginary [phasor~] tuned to fit the blocksize, times another constant.
_ _ __ ___ _____ ________ _____________ _____________________ ... | Mathieu Bouchard - tél:+1.514.383.3801 - http://artengine.ca/matju | Freelance Digital Arts Engineer, Montréal QC Canada