In my happy world, one could perform the following:
[coords 0 -1 1 1 80 90 1 100 100;( | | [s $!]
With the example above, one could perform canvas operations on the current canvas, ie: "this". So to answer your question, $! would be the equivalent to whatever name you supplied in [namecanvas], so it's type would be that of the canvas, an object type.
Therefore, if you attempted the following, no error should occur (again, in my happy world)
[clear( | | [s $1]
Miller?
Cheers, ~Brandon
On Thu, Sep 30, 2010 at 1:22 PM, Mathieu Bouchard matju@artengine.cawrote:
On Thu, 30 Sep 2010, brandon zeeb wrote:
If Miller wants to remove [namecanvas], just give us a "this" expression!
What about $! ?
What would be the type of $! ?
I don't think that there is any atom-type for supporting the feature that you suggest.
see also http://lists.puredata.info/pipermail/pd-list/2006-02/035454.html
| Mathieu Bouchard ------------------------------ Villeray, Montréal, QC