13 Jan
2008
13 Jan
'08
9:24 p.m.
You also have : |1 0.4( | [- ]
++
Jack
Le 13 janv. 08 à 19:55, Jamie Bullock a écrit :
On Sun, 2008-01-13 at 17:17 +0000, Jamie Bullock wrote:
The pd abstraction is essentially syntactic sugar, so instead of doing:
|0.4( | [t b a] | / |1( / | / [- ]
You can just do:
|0.4( | [! - 1]
As someone just pointed out to me, this is also syntactic sugar for
the leaner:[0.4( | [swap 1] \ / [- ]
Jamie
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