Re: [PD] 1 / 0 = 0?

Dear Christof,

I understand that tradeoff when working with real-time audio.

However, I was talking about control logic, not audio.

BH

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On Thu, May 24, 2018 at 10:57 AM, Christof Ressi christof.ressi@gmx.at wrote:

Hi William,

there's no other sane way to handle division by 0 in the audio domain since the result must be a number and there are only two options: output 0 or some ridiculously large number (which would be quite dangerous). Pd *could* handle it differently in the control domain, but why? as Matt said: just don't divide by 0 :-)

Christof

Gesendet: Donnerstag, 24. Mai 2018 um 16:52 Uhr Von: "Matt Davey" hard.off@gmail.com An: "William Huston" williamahuston@gmail.com Cc: "pd-list@lists.iem.at" pd-list@lists.iem.at Betreff: Re: [PD] 1 / 0 = 0? Just don’t allow your function to blow up in the first place.

On Thursday, May 24, 2018, William Huston <williamahuston@gmail.com[ mailto:williamahuston@gmail.com]> wrote:

I have a function which blows up at a certain point, moves to infinity. In this case, it is basically 1/0.

I was a little surprised to find that 1/0 = 0 (according to Pd). I was expecting NaN, or an overflow condition would could be trapped.

So what I have to do is examine the *input* for the values which will blow up my function, and set a flag. While this is easy in this single case, it is awkward in the general case.

This seems somewhat broken to me. Is this a bug?

Thanks BH

-- William Huston: WilliamAHuston@gmail.com[mailto:WilliamAHuston@gmail.com] Binghamton NY

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