18 Mar
2014
18 Mar
'14
10:32 p.m.
On 03/18/2014 04:05 PM, Alexandre Torres Porres wrote:
and as I was checking before, not too far from raising to the power of 0.25 (thicker line in the graph from the picture attached)
Btw-- here's what that patch looks like in Pd-l2ork (attached).
The array rectangle is orange because it's selected. I also changed the size of the garray by click-dragging with the mouse.
-Jonathan
2014-03-18 16:48 GMT-03:00 Alexandre Torres Porres <porres@gmail.com mailto:porres@gmail.com>:
the solution is as I thought, to just invert the given formula in the code. Someone helped me with the math, is something like expr ln($f1 / 1.27) / (((log(127 / 1.27) / 1.27)) * 0.01) here's a patch attached I'm finally gonna check what kind of curve this thing gives :) Thanks everyone Cheers 2014-03-18 5:13 GMT-03:00 Jonathan Wilkes <jancsika@yahoo.com <mailto:jancsika@yahoo.com>>: No, the code I ported is from vslider_set and vslider_draw_update (might be different in Vanilla). In vslider_bang, math is done to output the proper value. Without looking at the code I would have guessed vslider_bang simply outputs a stored value like [float] does. Then just do math to set the slider position or calculate a new stored value from mouse input. -Jonathan On Monday, March 17, 2014 1:21 AM, Alexandre Torres Porres <porres@gmail.com <mailto:porres@gmail.com>> wrote: Hi Roman. This is turning out trickier than I thought. A friend explained the code to me and got to the following equation, with min/max values as 0.01 and 1 respectively. [expr 0.01 * exp((log(1 / 0.01) / 0.01) * $f1 * 0.01)] For what I've checked, it seems to behave like your patch. But it doesn't do the trick I'm looking for yet. I sent a patch earlier, and I'm sending it back again. The goal is to connect a linear slider to an [expr] (with this so called "log" function) and then to another linear slider. The idea then is that this second slider behaves as one that was set as being "log". In the patch attached I was able to emulate it poorly with [pow 0.25], but that was before reaching the list. See that if I use this expr function from the code or your patch it presents quite a different behavior. maybe it is some sort of inversion of this equation, not sure. Apparently this code converts the "log" function values to linear and I'm hoping to get the exact opposite. Got it? Thanks for looking into this 2014-03-12 4:38 GMT-03:00 Roman Haefeli <reduzent@gmail.com>: On Don, 2014-03-06 at 21:37 -0300, Alexandre Torres Porres wrote: > hi folks, out of curiosity, what's the exact log function used in the > slider? I'd like to emulate it. I am not sure, if this is what you want. It converts the incoming linear range between 0 and 1 to a logarithmic range specified by $1 and $2, respectively by the second and third inlet. They behave like the lower and upper bound specified in the [vslider]/[hslider] classes. https://raw.github.com/reduzent/netpd2-patches/master/abs/rh_scalelog.pd Roman _______________________________________________ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list _______________________________________________ Pd-list@iem.at mailing list UNSUBSCRIBE and account-management -> http://lists.puredata.info/listinfo/pd-list
