[fexpr~ abs($x[0] - $x[-1]) > 0.5] [threshold~ 0.5 0 0.5 0]
sick
On Sat, Mar 2, 2019 at 7:31 PM Alexandre Torres Porres porres@gmail.com wrote:
connect output of [phasor~] into:
[fexpr~ abs($x[0] - $x[-1]) > 0.5]
then use:
[threshold~ 0.5 0 0.5 0]
Em sáb, 2 de mar de 2019 às 11:05, Claude Heiland-Allen < claude@mathr.co.uk> escreveu:
On 2019-03-02 13:20, Orm Finnendahl wrote:
is there some easy way in vanilla pd to get a bang on each phasor~ wraparound which doesn't involve polling with snapshot~?
https://lists.puredata.info/pipermail/pd-list/2006-12/044634.html
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