And we want f' to be 1 (integer step) / (per) quantization size (for that amplitude)
On 2 November 2010 19:41, Ludwig Maes ludwig.maes@gmail.com wrote:
The reason you use the inverse is so that the amplitude remains the same albeit quantized. The reason we use another function before flooring is to distritube the floor levels.But afterwards we need to bring the values back to their "original" place
On 2 November 2010 19:37, Ludwig Maes ludwig.maes@gmail.com wrote:
So you want amplitude 'a' dependant quantization size 'q' ? take your chosen q(a); in your example it seems you want a simple line: q=q(0)-k*a; define f(a) as integral of 1/q from a=0 to a; also calculate the inverse of f(a) i.e. a(f);
now for each sample do: out=a(round(f(in))) where round is any floor or the like...
have fun!
ps:
in your example: q=q0-k*a with for example q(0)=0.001 and q(0.8)=0.0001: q:=0.001-0.0009/0.8*a then f=2558.427881-1111.111111*ln(10.-9.*a) and inverse=easy
On 2 November 2010 19:20, Ludwig Maes ludwig.maes@gmail.com wrote:
This is pretty easy actually, I use such things mostly to guide my rhythmical quantization...
On 2 November 2010 19:19, brandon zeeb zeeb.brandon@gmail.com wrote:
This is even better. If I could minimize the jumps around Y = 0.5 to -0.5 It'll be exactly what I'm looking for... or a start at least.
Do you see what I mean now? See how the amount of quantization changes with Y and a minimum quantization value?
I think I'm getting towards the answer now...
-- Brandon Zeeb Columbus, Ohio