But can you post the correct code?
Sorry Matju, the correct code is now posted on cvs and of course works better than it did.If I guess correctly it's supposed to take the average distance between each possible pair of two distinct points? Then I have a O(n log n) algorithm for that, which has nothing to do with FFT. Yes, that's the idea. I would be very grateful to have a look at that.
Best, Ed
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