Hello,
This used to be a valid expression:
fexpr~$s3[$x1[0]] = $x2[0]; $s3[$x1[0]+22050] = $x2[0]
since last update of the expr library, this gives the following error:
expr: symbol cannot be a left value '$s3[$x1[0]] = $x2[0] ; $s3[$x1[0]+22050] = $x2[0]' expr_perform: bad result type 0
Any idea how I should rexrite the expression ?
Cheers
yog
Am 20. April 2025 10:34:24 MESZ schrieb Yogi data yogi.data@live.co.uk:
Hello,
This used to be a valid expression:
when?
(this question is not to imply that I believe that the expression never was valid, but in order to establish a rough timeline)
also, "expr" has long ceased to be a(n external) library (at least for Pd), so I wonder about which "expr-specific releases" you are talking about.
mfg.sfg.jfd IOhannes