Hi,<div><br></div><div>Just realised putting a negative number into the [pow] object outputs &#39;0&#39;?!?</div><div><br></div><div>For example if I do:</div><div><br></div><div>[-1 (</div><div>|</div><div>[pow 2]</div><div>

<br></div><div>it returns 0, where I would expect it to return 1.</div><div><br></div><div>Is this a known limitation or bug? Are there any work arounds if I want a variable power?</div><div><br></div><div>(I&#39;m running Pd 0.44.1 on OS X Mountain Lion)</div>

<div><br></div><div>Thanks,</div><div>Joe</div>