22 Apr
2013
22 Apr
'13
2:19 p.m.
Hi,
Just realised putting a negative number into the [pow] object outputs '0'?!?
For example if I do:
[-1 ( | [pow 2]
it returns 0, where I would expect it to return 1.
Is this a known limitation or bug? Are there any work arounds if I want a variable power?
(I'm running Pd 0.44.1 on OS X Mountain Lion)
Thanks, Joe