On Tue, Sep 24, 2013 at 6:32 PM, Simon Wise <simonzwise@gmail.com> wrote:
On 24/09/13 21:46, Funs Seelen wrote:
On Tue, Sep 24, 2013 at 3:35 PM, Alexandre Torres Porres
<porres@gmail.com>wrote:

so you're basically saying all i need to use is use only the real part,
right?


No, I meant that I have the idea that the imaginary part in the calculated
coefficients will disappear automatically if you add complex conjugates for
all poles and zeros, probably when somehow i^2 gets -1 somewhere. But I
must say I'm not a mathematician and not sure at all.

indeed it will ... a conjugate is the number with the imaginary part negated ... so adding a number and its conjugate will certainly end up with a real part only.

Yes, true, and the imaginary part disappears as well when multiplying if the real parts are equal, e.g.:

i^2 = -1, so ...

(0.5 + 0.5i) * (0.5 - 0.5i) = 0.25 + 0.25i - 0.25i - 0.25i^2 = 0.5
 


Simon


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