On 1/29/07, Chuckk Hubbard badmuthahubbard@gmail.com wrote:
w(n)-fb1*w(n-1)-fb2*w(n-2)=x(n) ff1*w(n)+ff2*w(n-1)+ff3*w(n-2)=y(n) so,
y(n)-fb1*y(n-1)-fb2*y(n-2)=ff1*x(n)+ff2*x(n-1)+ff3*x(n-2)
I got it now. I don't understand why both expressions are useful, but I see that they're the same.
-Chuckk