not sure this is working either, I'm getting negative values when testing it with count~ (only positive values)
2015-12-08 10:30 GMT-02:00 Christof Ressi christof.ressi@gmx.at:
It certainly is and I have no idea how that happened :-D. but it has no effect whatsoever. just delete the connection.
Gesendet: Dienstag, 08. Dezember 2015 um 13:20 Uhr Von: "Alexandre Torres Porres" porres@gmail.com An: "Christof Ressi" christof.ressi@gmx.at Cc: "pd-list@lists.iem.at" pd-list@lists.iem.at Betreff: Re: Re: [PD] Moving Sum object?
what was the purpose of the output from the max object into rpole~ in your patch? that's a bug, right?
cheers
2015-12-08 9:50 GMT-02:00 Christof Ressi christof.ressi@gmx.at:
Or are you talking about a object that outputs the sum as a message? In that case just use [cmavg~] or [maverage~] with [snapshot~]. If you just want the sum of a signal vector, there are some objects in zexy that will do the job, like [avg~] or [pack~]+[sum]
Gesendet: Dienstag, 08. Dezember 2015 um 12:41 Uhr Von: "Christof Ressi" <christof.ressi@gmx.at[christof.ressi@gmx.at]>
An: "Alexandre Torres Porres" <porres@gmail.com[porres@gmail.com]> Cc: "pd-list@lists.iem.at[pd-list@lists.iem.at]" <pd-list@lists.iem.at[ pd-list@lists.iem.at]> Betreff: Re: [PD] Moving Sum object?
Well, a linear moving average filter is just something that sums a series of samples. If you don't want the average but rather the true sum, either multiply the output by the number of samples or take my abstraction and get rid of the [/~] object.
Gesendet: Dienstag, 08. Dezember 2015 um 12:21 Uhr Von: "Alexandre Torres Porres" <porres@gmail.com[porres@gmail.com]> An: "Christof Ressi" <christof.ressi@gmx.at[christof.ressi@gmx.at]> Cc: "Matt Barber" <brbrofsvl@gmail.com[brbrofsvl@gmail.com]>, " pd-list@lists.iem.at[pd-list@lists.iem.at]" <pd-list@lists.iem.at[ pd-list@lists.iem.at]> Betreff: Re: Re: [PD] Moving Sum object?
cool guys, but i was asking for an average "sum" object :)
2015-12-08 9:19 GMT-02:00 Christof Ressi christof.ressi@gmx.at:Hey Matt,
there's no need for the feedback path (and therefore no [block~ 1] ;-))
Just use the following formula:
y[n] = (y[n-1] - x[n-k])/k
where k is the number of samples to be averaged (must be at least 1). see the patch I sent to Alex in my last mail. it uses [rpole~ 1] for the y[n-1] part and [z~ k] for the x[n-k] part (you can replace the latter one with a [delwrite~] [delread~] pair to make it purely vanilla).
The funny thing about linear moving average filters is, that although it can be implemented as a recursive filter (like in both our patches), it is still a FIR filter (and therefore it defeats the notion that recursive filters are always IIR filters). The impulse response is just a rectangular pulse and therefore finite.
Gesendet: Dienstag, 08. Dezember 2015 um 07:13 Uhr Von: "Matt Barber" brbrofsvl@gmail.com An: "Alexandre Torres Porres" porres@gmail.com Cc: "pd-list@lists.iem.at" pd-list@lists.iem.at Betreff: Re: [PD] Moving Sum object?
Something like this? Almost completely untestsed. :D
On Tue, Dec 8, 2015 at 12:20 AM, Alexandre Torres Porres porres@gmail.com wrote:
Talking about averages I wonder if we have an object that sums (in a moving average fashion) a series of samples
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