12 Oct
2011
12 Oct
'11
10:43 a.m.
On 11/10/2011 17:02, Mathieu Bouchard wrote:
Le 2011-10-11 à 12:42:00, Lorenzo Sutton a écrit :
No, no. I propose that with expr, expr~ and fexpr~ you count one object for each operator you use so: [expr~ sin($v1 + 1) * sqrt ($v1)] would be 4 objects :-)
[lop~] is essentially made from one [rpole~], one [*], one [/], one [samplerate~] and one [loadbang], so why wouldn't you count it as five ?
etcætera... how do you count [biquad~] ?
how do you count a [table] ?
Hey, hey.. I was joking :P
Still 16 objects, but then.. you can put it on when you get those oh so bothersome marketing calls.
Lorenzo