Sorry, that last example should read:
In my happy world, one could perform the following:[coords 0 -1 1 1 80 90 1 100 100;(||[s $!]With the example above, one could perform canvas operations on the current canvas, ie: "this". So to answer your question, $! would be the equivalent to whatever name you supplied in [namecanvas], so it's type would be that of the canvas, an object type.Therefore, if you attempted the following, no error should occur (again, in my happy world)[clear(||[s $1]Miller?Cheers,~BrandonOn Thu, Sep 30, 2010 at 1:22 PM, Mathieu Bouchard <matju@artengine.ca> wrote:
On Thu, 30 Sep 2010, brandon zeeb wrote:What would be the type of $! ?
If Miller wants to remove [namecanvas], just give us a "this" expression! What about $! ?
I don't think that there is any atom-type for supporting the feature that you suggest.
see also http://lists.puredata.info/pipermail/pd-list/2006-02/035454.html
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| Mathieu Bouchard ------------------------------ Villeray, Montréal, QC