On 10/16/2015 03:50 AM, Matt Barber wrote:
> Basically, for [block~] sizes less than 32 bits, [fft~] doesn't perform --
> it just passes the signal through unchanged.

isn't that what is expected of a 1 point FFT? (32bits == 4 bytes ==
sizeof(float)).

> See the attached patch, which only shows [fft~]. The saved contents of the
> tables on opening are the results for [block~ 8] on my machine, for
> quarter-nyquist at 44100.

so you meant 32 bytes (8 samples * 4 bytes each)?

or 32pins aka points (as in [block~ 32])?

gfmrdsa
IOhannes


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