If you normalize the output of the filter you describe to the same peak amplitude as the original, it's RMS value will certainly increase.  Having the peaks at a common reference point is critical.


-Theron
^

On Tue, Jan 11, 2011 at 10:33 AM, Mathieu Bouchard <matju@artengine.ca> wrote:
On Mon, 10 Jan 2011, Roman Haefeli wrote:

Assuming that the more compression is applied, the more the RMS amplitude [1] approaches the Peak amplitude [2] of an audio signal,

Why do you assume that ? Let's say I take a signal and divide it by its recent peak volume. The output of [osc~] will stay unchanged. A signal made of plenty of sharp spikes will have a much lower RMS/peak ratio and still be unchanged.

Are you confusing this with waveshaping such as [expr tanh($v1)] ? It may be a special case of compression, but is not what is usually meant by that.

http://en.wikipedia.org/wiki/Dynamic_range_compression


 _______________________________________________________________________
| Mathieu Bouchard ---- tél: +1.514.383.3801 ---- Villeray, Montréal, QC

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