29 Jan
2007
29 Jan
'07
6:24 a.m.
Hi Chuck. Thanks for the rundown. This mostly makes sense to me, except this:
w(n)-fb1*w(n-1)-fb2*w(n-2)=x(n) ff1*w(n)+ff2*w(n-1)+ff3*w(n-2)=y(n) so,
y(n)-fb1*y(n-1)-fb2*y(n-2)=ff1*x(n)+ff2*x(n-1)+ff3*x(n-2)
I can't seem to connect them. The dummy-variable equations seem unnecessarily dense. But, so there's nothing special about a biquad filter; just a 2nd-order IIR filter. -Chuckk