[list append] works with floats and symbols. ++
Jack
Le 15/10/2012 17:39, Charles Henry a écrit :
The arguments start from $1. $0 is a unique identifier per instance of an abstraction. The $1,...,$N strings work differently in messages and objects. $0 does nothing inside messages.
Just create an object [$1], send it a bang, and it dumps out the 1st argument of the abstraction it's in. I use it this way for floats. I think you need to declare it differently for strings/symbols. How about [symbol $1]?
Chuck
On Mon, Oct 15, 2012 at 10:19 AM, Charles Goyard cg@fsck.fr wrote:
Hi list,
I have an abstraction named "overlap". It takes an argument, such as "first" or "second".
This abstraction outputs a list. I would like this list to contain the argument. I tried with $0 from inside the abstraction to no avail. It looks like $0 is available only to send and receive ?
Maybe this sounds obvious, but I can't find the answer.
Thanks,
-- Charlot
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