7 Nov
2005
7 Nov
'05
11:45 p.m.
Hallo, Piotr Majdak hat gesagt: // Piotr Majdak wrote:
Chuckk Hubbard wrote:
i*sin(a) and i*sin(b) multiply to -sin(a)sin(b)?
let's forget the sin*sin and look at the i*i part only: since i = sqrt(-1) by definition, i*i is -1 (slowly: i*i= sqrt(-1)*sqrt(-1) = sqrt(-1 * -1) = sqrt((-1)^2) = -1)
Your equations are a bit, uhm, misleading, because (-1)^2 is 1, so sqrt(-1 * -1) = sqrt(1) = 1
Anyway, i is the unit, which fulfills the equation: i*i = -1
Ciao
Frank Barknecht _ ______footils.org_ __goto10.org__